2/5(x+3)^2+8=-32

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Solution for 2/5(x+3)^2+8=-32 equation: 



2/5(x+3)^2+8=-32

We move all terms to the left:

2/5(x+3)^2+8-(-32)=0



Domain of the equation: 5(x+3)^2!=0

x∈R



We add all the numbers together, and all the variables

2/5(x+3)^2+40=0

We multiply all the terms by the denominator


40*5(x+3)^2+2=0

Wy multiply elements

200x(x+2=0

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